Now another question $\displaystyle \int \frac{1}{\sqrt {x^2+a^2}}dx $
Follow Math Help Forum on Facebook and Google+
Sorry sorry I got it coz I have to make the substitution of x=tan u
Originally Posted by roshanhero Now another question $\displaystyle \int \frac{1}{\sqrt {x^2+a^2}}dx $ Note that if $\displaystyle a=0$ It will be easy. For the other values of a Substitute $\displaystyle x=a tan\theta$
View Tag Cloud