the lim as h-->0 of (|x+h|-|x|)/h at x=3 is A) -1 B) 0 C) 1 D) 3 E) nonexistent
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Originally Posted by rawkstar the lim as h-->0 of (|x+h|-|x|)/h at x=3 is A) -1 B) 0 C) 1 D) 3 E) nonexistent note that this is the definition of a derivative for the function f(x) = |x| remember what the graph of y = |x| looks like? so ... what is f'(3) = ?
f(3)=f(-3)?
nevermind I found that |x+h|-|x|=|h| so |h|/h=h/h=1
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