# Math Help - Solving Limit with Absolute Values

1. ## Solving Limit with Absolute Values

the lim as h-->0 of (|x+h|-|x|)/h at x=3 is
A) -1 B) 0 C) 1 D) 3 E) nonexistent

2. Originally Posted by rawkstar
the lim as h-->0 of (|x+h|-|x|)/h at x=3 is
A) -1 B) 0 C) 1 D) 3 E) nonexistent
note that this is the definition of a derivative for the function f(x) = |x|

remember what the graph of y = |x| looks like?

so ... what is f'(3) = ?

3. f(3)=f(-3)?

4. nevermind

I found that |x+h|-|x|=|h|
so |h|/h=h/h=1