Let f(x) = 1/x-3. Calculate the difference quotient F(0+h)-f(0)/h for
h =.1 = (-.114942587)
h =.01 = (-.1114827202)
h = -.01 = (-.1107419712)
h = -.1 = (-.1075268817)
I understood how to get these values but then it asked:
If the slope of the tangent line to the graph of F(x) at x = 0 was -1/n^2 for some integer n, what would you expect n to be?
n = ?
This is the part I do not understand, could someone please explain this to me.