Let f(x) = 1/x-3. Calculate the difference quotient F(0+h)-f(0)/h for

h =.1 = (-.114942587)

h =.01 = (-.1114827202)

h = -.01 = (-.1107419712)

h = -.1 = (-.1075268817)

I understood how to get these values but then it asked:

If the slope of the tangent line to the graph of F(x) at x = 0 was -1/n^2 for some integer n, what would you expect n to be?

n = ?

This is the part I do not understand, could someone please explain this to me.

Thank You,

Keith Stevens