Hi.
(Let, Int=integral and Sqrt=square root and In=natural log)
In a math book I found that
Int( Sqrt(Z^2-A^2) )
= (A^2)/2 * ( (Z*Sqrt(Z^2-A^2))/(A^2) - In((Z+sqrt(z^2-A^2))/A) )
= (Z*Sqrt(Z^2-A^2))/2 - ( (A^2)/2 * In((Z+sqrt(z^2-A^2))/A) )
but with my TI-89 titanium calculator the same integral gave
Int( Sqrt(Z^2-A^2) )
= (Z*Sqrt(Z^2-A^2))/2 - ( (A^2)/2 * In(Z+sqrt(z^2-A^2)) )
After some working out on paper, I found my calculator gave the wrong result. I not too sure why this is. Can anyone tell me which is correct ?
Thanks


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