the slope of the line 3y-2x = 4 is 2/3
you want the pts where the derivative of sec(x) = sec(x)tan(x) = 2/3
To solve convert to sines to obtain eqn
2sin^(x) + 3sin(x) -2 = 0
This is easily factored and solved
Find the points on the graph of y = sec x, 0 ≤ x ≤ 2pi, where the tangent is parallel to the line 3y - 2x = 4.
How exactly do i find this? I assume you take the derivative but then what? (if that's even correct)
Thanks for any help! :P