Attachment 14707

I found

then Area = with upper limit c and lower a.

I then let x = acosht, is this correct?

then did the method of substitution.

then what do I do? My end answer looks very weird...so i just want to make sure.

- Jan 7th 2010, 10:34 AMAerospankHow do you calculate the area under hyperbola?is this correct? what do I do next?
Attachment 14707

I found

then Area = with upper limit c and lower a.

I then let x = acosht, is this correct?

then did the method of substitution.

then what do I do? My end answer looks very weird...so i just want to make sure. - Jan 7th 2010, 01:14 PMshawsend
Solve it parametrically if we know that the parametric representation of the right side of a hyperbola is given by . So then the area is:

.

You can find the limits in terms of t right? - Jan 7th 2010, 02:52 PMAerospank
- Jan 7th 2010, 04:08 PMshawsend
Yes, that's fine what you did. Sorry, I didn't notice that initially. And you know of course to express the limits of integration in t which I get: