How can we integrate sec x? Please give me only hint.

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- Jan 6th 2010, 07:42 AMroshanheroIntegrate sec x
How can we integrate sec x? Please give me only hint.

- Jan 6th 2010, 07:44 AMDrexel28
- Jan 6th 2010, 08:09 AMCalculus26
another way is to multiply and divide sec(x) by (secx +tan(x) to obtain

[sec^2(x) +sec(x)tan(x)]/[sec(x)+tan(x)]

Then let u = sec(x) +tan(x)

du = [ sec^2(x) +sec(x)tan(x)]dx

you end up with integral[du/u] = ln(u) - Jan 6th 2010, 08:10 AMKrizalid
Multiply top and bottom by $\displaystyle \sec x+\tan x.$ (Got beaten.)

- Jan 6th 2010, 08:42 AMShanks
multiply top and bottom by $\displaystyle \cos x$.

- Jan 6th 2010, 08:46 AMCalculus26
Don't really see what multiplying top and bottom by cos(x) does for you??

- Jan 6th 2010, 08:55 AMShanks
- Jan 6th 2010, 08:56 AMDrexel28