Two parts to this problem:

1. Show that the area of the ellipse $\displaystyle \frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ is $\displaystyle {\pi}ab$;

2. Find the volume enclosed by the ellipsoid $\displaystyle \frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1$ by integrating the area of a horizontal cross section.

I can't find any similar examples in my textbook and I am really stumped on this one, I'm taking a guess that this is meant to be solved by double integrals? If so, I am terrible at setting those up >.< If someone could point me in the right direction for solving it would help a lot =)