# Thread: Another line integral

1. ## Another line integral

int(ydx + xdy); C is the curve y=x^2, 0 <= x <= 1

Thanks

2. Originally Posted by pakman
int(ydx + xdy); C is the curve y=x^2, 0 <= x <= 1

Thanks
I have little time (might be wrong).
It seems that,
f(x,y)=xy
Is a scalar potential.

Thus, by the fundamental theorem of line integrals,
f(1,1)-f(0,0)=1

3. Originally Posted by ThePerfectHacker
I have little time (might be wrong).
It seems that,
f(x,y)=xy
Is a scalar potential.

Thus, by the fundamental theorem of line integrals,
f(1,1)-f(0,0)=1
I figured it out actually.

Since y is not changing, dy = 0 thereby removing the xdy part of the function.

int(y dx) is all that remains. Plug in x^2.

int(x^2 dx) which equals 2 after integrating from 0 to 1.