how do you find the derivative of (ln x)^sin x

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- Jan 4th 2010, 04:39 PMspazzyskylarDerivative help, please
how do you find the derivative of (ln x)^sin x

- Jan 4th 2010, 04:41 PMJhevon
- Jan 4th 2010, 04:42 PMspazzyskylar
Yeah, but every time I do it I screw it up..

- Jan 4th 2010, 04:43 PMJhevon
- Jan 4th 2010, 04:53 PMspazzyskylar
For my answer I ended up with...

y'= y(sinx+cosx*ln(ln x) - Jan 4th 2010, 04:55 PMJhevon
- Jan 4th 2010, 05:22 PMspazzyskylar
I thought I did in what I wrote down...

- Jan 4th 2010, 05:32 PMskeeter

- Jan 4th 2010, 05:34 PMmr fantastic