Hi

Need help to express the following in partial fractions:

$\displaystyle \frac{x^2-2}{(x+1)(x-2)}$

P.S

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- Jan 4th 2010, 04:22 PMPaymemoneyPartial Fractions Question
Hi

Need help to express the following in partial fractions:

$\displaystyle \frac{x^2-2}{(x+1)(x-2)}$

P.S - Jan 4th 2010, 04:30 PMpickslides
What do you need to do with this expression?

The order of the numerator is the same as the denominator, you may not need to make partial fractions.

If you need to consider

$\displaystyle \frac{x^2-2}{(x+1)(x-2)} = \frac{A}{x+1}+\frac{B}{x-2}$

$\displaystyle x^2-2 = A(x-2)+B(x+1)$

choose values for x to solve for A and B. - Jan 4th 2010, 04:36 PMskeeter
$\displaystyle \frac{x^2-2}{(x+1)(x-2)} = $

$\displaystyle \frac{x^2-2}{x^2-x-2} = $

$\displaystyle \frac{x^2-x-2+x}{x^2-x-2} = $

$\displaystyle \frac{x^2-x-2}{x^2-x-2} + \frac{x}{x^2-x-2} = $

$\displaystyle 1 + \frac{x}{(x+1)(x-2)}$

now use the method of partial fractions on $\displaystyle \frac{x}{(x+1)(x-2)}$ - Jan 4th 2010, 04:45 PMPaymemoney
- Jan 4th 2010, 04:49 PMskeeter