Hello asked why $\displaystyle sin (mx)\approx{mx}$ A greeting and thanks
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Originally Posted by Dogod11 Hello asked why $\displaystyle sin (mx)\approx{mx}$ A greeting and thanks For small values of $\displaystyle x$. What is $\displaystyle \lim_{x\to0}\frac{\sin(mx)}{mx}$?
Originally Posted by Dogod11 Hello asked why $\displaystyle sin (mx)\approx{mx}$ A greeting and thanks when x is close to 0, $\displaystyle \sin(mx) \approx mx$ because $\displaystyle \lim_{x \to 0} \frac{\sin(mx)}{mx} = 1$
Originally Posted by Dogod11 Hello asked why $\displaystyle sin (mx)\approx{mx}$ A greeting and thanks This is true for very small x.
Hi, Thank you very much
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