Finding a derivative

**pocketasian** · Jan 3rd 2010, 06:43 PM

Hello, how do I find dy/dx of

Please work it out for me to see rather than just give an answer. Thanks!
And also, since I'm still trying to figure out LaTex, will you show me how to display this equation using this coding?

**Archie Meade** · Jan 3rd 2010, 06:46 PM

Use the derivative for $y=a^x$ and use the chain rule for the index.

**pocketasian** · Jan 3rd 2010, 06:50 PM

Originally Posted by Archie Meade

Use the derivative for $y=a^x$ and use the chain rule for the index.

So would it be
2x ln10 10^[(x^2)-1] ?
Please excuse my lack of coding.

**Archie Meade** · Jan 3rd 2010, 07:00 PM

The $ln10$ will be a denominator, otherwise yes.

**skeeter** · Jan 3rd 2010, 07:07 PM

Originally Posted by Archie Meade

The $ln10$ will be a denominator, otherwise yes.

his derivative is correct.

$\frac{d}{dx} (a^u) = a^u \cdot \ln{a} \cdot \frac{du}{dx}$

$\int a^u \, du = \frac{a^u}{\ln{a}} + C$

**Archie Meade** · Jan 4th 2010, 03:13 AM

yes!
i accidentally gave the version from the integral.

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