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Math Help - Calculating y'

  1. #1
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    Calculating y'

    The problem is y= e^sin2x

    I never learned how to do this before break and it's in my packet for calc. Can someone give me guidelines for the steps I need to take to solve this?
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  2. #2
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    Quote Originally Posted by spazzyskylar View Post
    The problem is y= e^sin2x

    I never learned how to do this before break and it's in my packet for calc. Can someone give me guidelines for the steps I need to take to solve this?
    If y = e^f(x)
    then y`= (e^f(x)) f`(x)
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  3. #3
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    So then y'= (e^sin2x)2cos2x
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  4. #4
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    For y= e^{\sin(2x)}

    Apply the rule

    y= e^{f(x)}\implies y'= f'(x)e^{f(x)}
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  5. #5
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    Quote Originally Posted by spazzyskylar View Post
    So then y'= (e^sin2x)2cos2x


    y'= 2\cos(2x)e^{\sin(2x)}
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  6. #6
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    Awesome, thanks
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