Thread: Calculating y'

The problem is y= e^sin2x

I never learned how to do this before break and it's in my packet for calc. Can someone give me guidelines for the steps I need to take to solve this?

Originally Posted by spazzyskylar

The problem is y= e^sin2x

I never learned how to do this before break and it's in my packet for calc. Can someone give me guidelines for the steps I need to take to solve this?

If y = e^f(x)
then y`= (e^f(x)) f`(x)

So then y'= (e^sin2x)2cos2x

For

Apply the rule

Originally Posted by spazzyskylar

So then y'= (e^sin2x)2cos2x

Awesome, thanks