# Math Help - Calculating y'

1. ## Calculating y'

The problem is y= e^sin2x

I never learned how to do this before break and it's in my packet for calc. Can someone give me guidelines for the steps I need to take to solve this?

2. Originally Posted by spazzyskylar
The problem is y= e^sin2x

I never learned how to do this before break and it's in my packet for calc. Can someone give me guidelines for the steps I need to take to solve this?
If y = e^f(x)
then y= (e^f(x)) f(x)

3. So then y'= (e^sin2x)2cos2x

4. For $y= e^{\sin(2x)}$

Apply the rule

$y= e^{f(x)}\implies y'= f'(x)e^{f(x)}$

5. Originally Posted by spazzyskylar
So then y'= (e^sin2x)2cos2x

$y'= 2\cos(2x)e^{\sin(2x)}$

6. Awesome, thanks