The problem is y= e^sin2x I never learned how to do this before break and it's in my packet for calc. Can someone give me guidelines for the steps I need to take to solve this?
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Originally Posted by spazzyskylar The problem is y= e^sin2x I never learned how to do this before break and it's in my packet for calc. Can someone give me guidelines for the steps I need to take to solve this? If y = e^f(x) then y`= (e^f(x)) f`(x)
So then y'= (e^sin2x)2cos2x
For $\displaystyle y= e^{\sin(2x)}$ Apply the rule $\displaystyle y= e^{f(x)}\implies y'= f'(x)e^{f(x)}$
Originally Posted by spazzyskylar So then y'= (e^sin2x)2cos2x $\displaystyle y'= 2\cos(2x)e^{\sin(2x)}$
Awesome, thanks
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