The problem is y= e^sin2x

I never learned how to do this before break and it's in my packet for calc. Can someone give me guidelines for the steps I need to take to solve this?

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- Jan 3rd 2010, 12:17 PMspazzyskylarCalculating y'
The problem is y= e^sin2x

I never learned how to do this before break and it's in my packet for calc. Can someone give me guidelines for the steps I need to take to solve this? - Jan 3rd 2010, 12:20 PMTWiX
- Jan 3rd 2010, 12:27 PMspazzyskylar
So then y'= (e^sin2x)2cos2x

- Jan 3rd 2010, 12:30 PMpickslides
For $\displaystyle y= e^{\sin(2x)}$

Apply the rule

$\displaystyle y= e^{f(x)}\implies y'= f'(x)e^{f(x)}$ - Jan 3rd 2010, 12:32 PMpickslides
- Jan 3rd 2010, 12:34 PMspazzyskylar
Awesome, thanks :)