# Calculating y'

• January 3rd 2010, 12:17 PM
spazzyskylar
Calculating y'
The problem is y= e^sin2x

I never learned how to do this before break and it's in my packet for calc. Can someone give me guidelines for the steps I need to take to solve this?
• January 3rd 2010, 12:20 PM
TWiX
Quote:

Originally Posted by spazzyskylar
The problem is y= e^sin2x

I never learned how to do this before break and it's in my packet for calc. Can someone give me guidelines for the steps I need to take to solve this?

If y = e^f(x)
then y= (e^f(x)) f(x)
• January 3rd 2010, 12:27 PM
spazzyskylar
So then y'= (e^sin2x)2cos2x
• January 3rd 2010, 12:30 PM
pickslides
For $y= e^{\sin(2x)}$

Apply the rule

$y= e^{f(x)}\implies y'= f'(x)e^{f(x)}$
• January 3rd 2010, 12:32 PM
pickslides
Quote:

Originally Posted by spazzyskylar
So then y'= (e^sin2x)2cos2x

(Nod)

$y'= 2\cos(2x)e^{\sin(2x)}$
• January 3rd 2010, 12:34 PM
spazzyskylar
Awesome, thanks :)