can someone help me with this double integral please.
DOUBLE INTEGRAL: e^-r^2 r dr dtheta
where r is bounded by 0 and a
and theta is bounded by 0 and pi/2
thanks
Hello, mesterpa!
It seems to be easy enough . . .
Can someone help me with this double integral please.
∫∫ e^{-r²} r dr dθ
. . where r is bounded by 0 and a
. . and θ is bounded by 0 and π/2
The inner integral is: .∫ e^{-r²} r dr
Let: u = -r² . → . du = -2r dr
And we have: .-½∫ e^u du .= .-½ e^u . → . -½e^{-r²}
Now evaluate for r = 0 to r = a.
Then integrate with respect to θ and evaluate.