1. ## Help with problem

If g(x)=sin(cos(x^2)), find the equation of the tangent line at the point where x=(squareroot)(Pie/2). Use this linerariztion to approximate g(5/4).

I'm lost with this problem. I new to this sorry if it hard to read. Thanks

2. use the chain rule and set to $\sqrt{\frac{\pi}{2}}$. '

derivatives: $sin(x)'=cos(x)
$

$cos(x)'=-sin(x)$

3. Originally Posted by integral
use the chain rule and set to $\sqrt{\frac{\pi}{2}}$. '

edit: The chain rule is:
if
$y=\frac{f}{g}$
then
$y'=\frac{g(f')-f(g')}{g^2}$
No, that is NOT the chain rule, that is the quotient rule.

The chain rule says that the derivative of f(g(x)) is $\frac{df}{dg}\frac{dg}{dx}$

derivatives: $sin(x)'=cos(x)
$

$cos(x)'=-sin(x)$