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Thread: Help with problem

  1. #1
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    Help with problem

    If g(x)=sin(cos(x^2)), find the equation of the tangent line at the point where x=(squareroot)(Pie/2). Use this linerariztion to approximate g(5/4).

    I'm lost with this problem. I new to this sorry if it hard to read. Thanks
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  2. #2
    Member integral's Avatar
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    use the chain rule and set to $\displaystyle \sqrt{\frac{\pi}{2}}$. '




    derivatives:$\displaystyle sin(x)'=cos(x)
    $
    $\displaystyle cos(x)'=-sin(x)$
    Last edited by integral; Jan 2nd 2010 at 11:41 AM.
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  3. #3
    MHF Contributor

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    Quote Originally Posted by integral View Post
    use the chain rule and set to $\displaystyle \sqrt{\frac{\pi}{2}}$. '

    edit: The chain rule is:
    if
    $\displaystyle y=\frac{f}{g}$
    then
    $\displaystyle y'=\frac{g(f')-f(g')}{g^2}$
    No, that is NOT the chain rule, that is the quotient rule.

    The chain rule says that the derivative of f(g(x)) is $\displaystyle \frac{df}{dg}\frac{dg}{dx}$


    derivatives:$\displaystyle sin(x)'=cos(x)
    $
    $\displaystyle cos(x)'=-sin(x)$
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