use the chain rule and set to . '

derivatives:

Results 1 to 3 of 3

- January 1st 2010, 08:39 PM #1

- Joined
- Jan 2010
- Posts
- 2

- January 1st 2010, 09:02 PM #2

- January 2nd 2010, 04:19 AM #3

- Joined
- Apr 2005
- Posts
- 16,958
- Thanks
- 2007