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Math Help - please graph these 2 graphs

  1. #1
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    please graph these 2 graphs

    hello.

    please graph these two

    f(x)=(x^2-1)(1-x/2), also if you could find the real zeros of this polynomial



    f(x)=x^2+3x+2/x-1

    thanks
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  2. #2
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    Quote Originally Posted by girl1985 View Post
    hello.

    please graph these two

    f(x)=(x^2-1)(1-x/2), also if you could find the real zeros of this polynomial
    ...
    Hi,

    you can factor the term of the function completely:

    f(x) = (x - 1)(1 - x/2) = (x - 1)(x + 1)(x - x/2)

    A product equals zero if one of the factors is zero. Therefore solve for x;

    x + 1 = 0 or x - 1 = 0 or 1 - x/2 = 0. You'llget the zeros: -1, 1, 2

    I've attached the graph of the function.

    EB
    Attached Thumbnails Attached Thumbnails please graph these 2 graphs-nullst_polygrad.gif  
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  3. #3
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    Quote Originally Posted by girl1985 View Post
    hello.

    please graph these two
    ...
    f(x)=x^2+3x+2/x-1
    Hi,

    I'm not quite certain how to read this problem. I assume that you mean:

    f(x)=x^2+3x+2/(x-1)

    The graph has a vertical asymptote at x = 1 because the function is not defined at x = 1.

    To calculate the zeros you have to solve an equation of 3rd degree:

    x + 2x - 3x + 2 = 0. The solution is possible if you use Cardano's formula. It's a lot of work so I let my computer do it.

    You get only one zero at x -3.15275...

    I've attached a diagram of the graph. The asymptote is painted red.

    EB
    Attached Thumbnails Attached Thumbnails please graph these 2 graphs-nullst_gebrpoly.gif  
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  4. #4
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    Quote Originally Posted by girl1985 View Post
    hello.

    please graph these two
    f(x)=x^2+3x+2/x-1

    thanks
    Hi,

    I'm not quite certain how to read this problem. I assume that you mean:

    f(x)=x^2+3x+2/x-1

    The graph has a vertical asymptote at x = 0 because the function is not defined at x = 0.

    To calculate the zeros you have to solve an equation of 3rd degree:

    x + 3x - x + 2 = 0. The solution is possible if you use Cardano's formula. It's a lot of work so I let my computer do it.

    You get only one zero at x = -3.4566...

    I've attached a diagram of the graph. The asymptote is painted red.

    EB
    Attached Thumbnails Attached Thumbnails please graph these 2 graphs-nullst_gebrpoly2.gif  
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