Equation of the circle is x^2 + y^2 = r^2
and the sector's angle = x
That is derived from the equation of the circle! But if you want to do it in the hard way, using Cartesian coordinates, you can without loss of generality, assume one edge of the sector lies on x axis, from x= 0 to x= r. The other then lies on the line from x=0 to . Part of the area, then, is given by which is easy since r and are constants. But then you have to find the area of the portion under the circular arc, . That is . The total area of the sector is the sum of those integrals:
I think using polar coordinates is a much better idea. Of course, as a check, since a central angle of cuts of the entire circle, its area is that same fraction of the entire area of the circle, .