The height of an object moving vertically is given by:
s=-16t^2+96t+112
with s in ft and t in sec. Find a) the object's velocity when t=0 b) its maximum height and when it occurs, and c) its velocity when s=0
I don't even know where to start
The height of an object moving vertically is given by:
s=-16t^2+96t+112
with s in ft and t in sec. Find a) the object's velocity when t=0 b) its maximum height and when it occurs, and c) its velocity when s=0
I don't even know where to start
Don't treat it as a physics question.
Find the vertex ($\displaystyle \frac{-b}{2a}$)
Then plug in two random numbers (neg and pos) to find the other two points and graph.
(t is just x so look at the x axis for t)
t=0 is when the parabola hits the y axis. (I.e. Just set everything multiplied by t to 0)
max height is just the vertex.
(and for velocity at s=0 just set the equation equal to =0)sorry I thought v=s