I need to find the square root of:

The answer I got is:

Is this correct? if not please explain.

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- Dec 31st 2009, 12:01 PMbearhugDerivative of Squareroot
I need to find the square root of:

The answer I got is:

Is this correct? if not please explain. - Dec 31st 2009, 12:25 PMvonflex1
the answer is actually: f'(x) = x / 2*(sqrt(x^2+15)

because: f(x) = (x^2+15)^(1/2)

so: f'(x) = (1/2)*(x^2+15)^(-1/2)*x <------ the inner derivative

and finally: f'(x) = x / 2*(sqrt(x^2+15) - Dec 31st 2009, 12:26 PMbearhug
wouldn't the inner derivative be 2x? since it was x^2

- Dec 31st 2009, 12:27 PMvonflex1
my bad... your answer was correct...

- Dec 31st 2009, 12:28 PMbearhug
great...thank you :)