Triple Integral

**james121515** · December 31st 2009, 02:12 AM

Hi,

My goal is to set up a triple integral that representshe the volume under the plane $z = 6$ , and inside the paraboloid $z = x^2 + y^2$ . I attempted to do this using cylindrical coodinates, and this is what I got:

$<br /> \int_0^{2\pi} \int_0^{\sqrt{6}}\int_{r^2}^{6} 1dzrdrd\theta<br />$

does it this look about right?
Thanks for any help
james

**HallsofIvy** · December 31st 2009, 04:29 AM

Originally Posted by james121515

Hi,

My goal is to set up a triple integral that representshe the volume under the plane $z = 6$ , and inside the paraboloid $z = x^2 + y^2$ . I attempted to do this using cylindrical coodinates, and this is what I got:

$<br /> \int_0^{2\pi} \int_0^{\sqrt{6}}\int_{r^2}^{6} 1dzrdrd\theta<br />$

does it this look about right?
Thanks for any help
james

Yes, that is correct.

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