if p=q-1. and$\displaystyle h_{k}=ph_{k+1}+qh_{k-1}$ and $\displaystyle h_{1}=ph_{2}+q$ for k=1 than how by using difference equation theory is a G.S $\displaystyle h_{k}=A+B(\frac{q}{p})^k$? I can just about see where you get$\displaystyle 1^k$ but not$\displaystyle (\frac{q}{p})^k$ thanks