You have 4 planes in :
So you must have 4 normals, one for each:
And remember that they must be exteriors to the enclosed region.
** See attachment**
I'm having a hard time trying to figure out how to get outward unit normals for each surface of this shape. Here I have the question and the answer but still don't seem to be able to solve it..
I understand that to get a unit normal I divide by the length of n but I cant see how the answer is
S1: x = 0 and n (hat) = (-1,0,0)
S2: y = 0 and n (hat) = (0,-1,0)
S3: z = 0 and n (hat) = (0,0,-1)
is it..
for S1: nabla ( 3y + 2z -6 )
so is the unit normal
1/(sqrt(11))*(0,3,2) ????
If so then the answers I have are wrong!
Please can someone help. I have included the problem in the attachment.
No, what did you do, solve for -6x?
S1 is the plane x= 0.
S2 is the plane y= 0.
S3 is the plane z= 0.
those already have unit length.
S4 is the plane 6x+ 3y+ 2z= 6 so . Its length is .
so is the unit normal
1/(sqrt(11))*(0,3,2) ????
If so then the answers I have are wrong!
Please can someone help. I have included the problem in the attachment.