y = (1-x)*ln(1-x) has a line att Xminimum. What is the equation of the line in exakt form?
Hint was: Find the x' and x'':
Thanks in advance Henry from Sweden
Henry ... you need to post these calculus questions in the calculus forum, not precalculus.
w/r to your derivative ...
$\displaystyle y = (1-x) \cdot \ln(1-x)$
use the product rule ...
$\displaystyle y' = (1-x) \cdot \left(\frac{-1}{1-x} \right) + \ln(1-x) \cdot (-1)$
$\displaystyle y' = -[1 + \ln(1-x)]$
$\displaystyle y'' = \frac{1}{1-x}$
I'm not really sure about your request for the equation of a line?