How do you find the maximum value of (ln(x))/x^2
First i derived: That gave me: (1-2ln(x))/x^3
Now i figure x' is zero at: x = 0
or ln(x) = 0,5 = e^0,5
But the correct answer is suppose to be 1/(2e)
What am i doing wrong?
With Kind regards Henry from Sweden