Hi

I have two limits i would like some help with

first one:

$\displaystyle \lim \limits_{x \to 0}\frac{10^x-e^x}{x}$

and second one

$\displaystyle \lim \limits_{x \to \infty} x(2tan^{-1}x-\pi)$

The first limit i thought could be rewritten like this [Math]\frac{e^{x*ln10}-e^x}{x}[/tex]

which would then be simplified down to:

$\displaystyle \frac{10e^x-e^x}{x} $

and then using L'Hopital rule to aquire 9

The last one i don't know how to start