let f and g be differentiable functions such that f(1)=4, g(1)=3, f '(3)=-5, f '(1)=-4, g '(1)=-3, g '(3)=2 if h(x)=f(g(x)), then h '(1)= ? please help
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Originally Posted by rawkstar let f and g be differentiable functions such that f(1)=4, g(1)=3, f '(3)=-5, f '(1)=-4, g '(1)=-3, g '(3)=2 if h(x)=f(g(x)), then h '(1)= ? please help $\displaystyle h(x) = f[g(x)]$ $\displaystyle h'(x) = f'[g(x)] \cdot g'(x)$ $\displaystyle h'(1) = f'[g(1)] \cdot g'(1)$ $\displaystyle h'(1) = f'(3) \cdot g'(1) = (-5) \cdot (-3) = 15$
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