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**alexandrabel90** find the limit of ( 9x +1 ) ^( cot x) as x tends to 0 from the positive direction.

to solve this question, i let y = ( 9x +1 ) ^( cot x)

hence ln y = (cot x) ln (9x+1)

as x tends to 0 from the positive direction, y tends to 1.

No, it doesn't....why do you think so??

lim exp ( ln y) = exp ( lim (ln y)) = exp (0) = 1

but if i were to check back my answers, i did not get an answer of 1.

here is my working:

lim exp ( ln y) = exp ( lim (ln y)) = exp ( lim ( cot x ln ( 9x +1))) = exp (lim ( ln ( 9x +1 ) / tan x )) = exp ( 9 cos ^2 x / ( 9x+1)) by l hopital rule.

which will give me exp (9) instead of my answer of exp (o).

thanks!