if
find
You need to use the chain rule multiple times, and set the work out carefully.
Chain rule 1: Let $\displaystyle u = x + \sqrt{x + \sqrt{x}}$.
Then $\displaystyle y = \sqrt{u}$ and $\displaystyle \frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}$.
Chain rule 2: To get $\displaystyle \frac{du}{dx}$, you will need to let $\displaystyle v = x + \sqrt{x}$.
Then $\displaystyle u = x + \sqrt{v}$ and $\displaystyle \frac{du}{dx} = 1 + \frac{d \sqrt{v}}{dx} = 1 + \frac{d \sqrt{v}}{dv} \cdot \frac{dv}{dx}$.
Now put it all together.
Just in case a picture helps...
... because...
... where
... is the chain rule. Straight continuous lines differentiate downwards (integrate up) with respect to x, and the straight dashed line similarly but with respect to the dashed balloon expression (the inner function of the composite which is subject to the chain rule).
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Don't integrate - balloontegrate!
Balloon Calculus; standard integrals, derivatives and methods
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