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Math Help - Trig substitution (just checking)

  1. #1
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    Trig substitution (just checking)

    I'm pretty sure i can do this i just want to make sure....thanx

    using trig substitution solve the following:

    The integral of sqrt(1-x) / sqrt(x)
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  2. #2
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    Quote Originally Posted by abcocoa View Post
    I'm pretty sure i can do this i just want to make sure....thanx

    using trig substitution solve the following:

    The integral of sqrt(1-x) / sqrt(x)
    Trig substitution? Then maybe you mean sqrt(1 -x^2) for the numerator?
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  3. #3
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    Re:

    The answer to this problem is

    g(x)=\sqrt{x}*\sqrt{1-x}+sin^-1(\sqrt{x})
    Last edited by qbkr21; March 4th 2007 at 11:16 AM.
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  4. #4
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    ?

    to qbk21 what does that mean and how did you get it? My problem is i'm not sure i'm doing the integral correctly and your answer doesn't make sense.

    Also it is sqrt(1-x)
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  5. #5
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    Re:

    Go to the following links

    Step #1: http://i137.photobucket.com/albums/q...1/SCREEN01.jpg

    Step #2: http://i137.photobucket.com/albums/q...1/SCREEN02.jpg

    Step #3: http://i137.photobucket.com/albums/q...1/SCREEN03.jpg



    Here, I have made it easy for you to integrate this problem.

    Just follow the steps.

    Best of Luck!
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  6. #6
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    Quote Originally Posted by abcocoa View Post
    I'm pretty sure i can do this i just want to make sure....thanx

    using trig substitution solve the following:

    The integral of sqrt(1-x) / sqrt(x)
    Here is what to do.

    Let t=sqrt(x) then, the integral becomes,

    2*INT sqrt(1-t^2)dt

    To do this with trigonometric substitution, use,
    u=asin(t)
    To get the answer.
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  7. #7
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    Re:

    Is my way of doing it correct PerfectHacker?
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  8. #8
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    Quote Originally Posted by abcocoa View Post
    I'm pretty sure i can do this i just want to make sure....thanx

    using trig substitution solve the following:

    The integral of sqrt(1-x) / sqrt(x)
    try this page

    integration by substitution
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  9. #9
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    Re:

    I was right!
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  10. #10
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    Using trig. substitution

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