approximate the root of h(x)=x^3 -3 using Newton's Method (correct to hundrehts)

Printable View

- December 21st 2009, 03:14 PMwisezetaNewton's Method
approximate the root of h(x)=x^3 -3 using Newton's Method (correct to hundrehts)

- December 21st 2009, 03:22 PMpickslides
Hi there, have a look at this post.

http://www.mathhelpforum.com/math-he...ngly-easy.html

make your starting guess - December 21st 2009, 03:23 PMskeeter
- December 21st 2009, 03:33 PMwisezeta
The actual root is 1.442, but the answer I get using 1.5 as my estimation gives me 1.5556. Is this right?

- December 21st 2009, 03:47 PMpickslides
Are you converging on this figure? how many iterations have you done?

- December 21st 2009, 03:48 PMskeeter
sorry for the typo ... the iteration equation should be a minus

try it again.