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Math Help - Finding derivative of function

  1. #1
    Junior Member xterminal01's Avatar
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    Finding derivative of function

    f(x) = x^2 arctan(x)

    arctan(x`) => X`/(1+x^2)
    Then..
    x^2(1/1+(x)^2)
    = x^2/1+x^2
    Is this done correctly?
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  2. #2
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    Quote Originally Posted by xterminal01 View Post
    f(x) = x^2 arctan(x)

    arctan(x`) => X`/(1+x^2)
    Then..
    x^2(1/1+(x)^2)
    = x^2/1+x^2
    Is this done correctly?
    no,that's not right.
    f'(x)=x^2/(x^2+1)+2x \arctan(x)
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  3. #3
    Junior Member xterminal01's Avatar
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    Where does the +2x arctan(x) come from?

    Quote Originally Posted by Raoh View Post
    no,that's not right.
    f'(x)=x^2/(x^2+1)+2x \arctan(x)
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  4. #4
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    Quote Originally Posted by xterminal01 View Post
    Where does the +2x arctan(x) come from?
    the derivative of the product.
    (f\times g)'=f'\times g+f\times g'.
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  5. #5
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    Quote Originally Posted by Raoh View Post
    the derivative of the product.
    (f\times g)'=f'\times g+f\times g'.
    anyway i think u have a problem,
    (\arctan(x))'=\frac{1}{1+x^2}
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