f(x) = $\displaystyle x^2 arctan(x)$

$\displaystyle arctan(x`) => X`/(1+x^2)$

Then..

$\displaystyle x^2(1/1+(x)^2)$

$\displaystyle = x^2/1+x^2$

Is this done correctly?

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- Dec 18th 2009, 01:40 PMxterminal01Finding derivative of function
f(x) = $\displaystyle x^2 arctan(x)$

$\displaystyle arctan(x`) => X`/(1+x^2)$

Then..

$\displaystyle x^2(1/1+(x)^2)$

$\displaystyle = x^2/1+x^2$

Is this done correctly? - Dec 18th 2009, 01:44 PMRaoh
- Dec 18th 2009, 01:47 PMxterminal01
- Dec 18th 2009, 01:51 PMRaoh
- Dec 18th 2009, 01:53 PMRaoh