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Math Help - Implicit differentiation

  1. #1
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    Implicit differentiation

    could you tell me how to attack this one

    Last edited by mr fantastic; December 17th 2009 at 04:00 PM. Reason: Moved from another thread.
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  2. #2
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    Quote Originally Posted by Da Freak View Post
    thanks a lot man.

    could you tell me how to attack this one too
    implicit differentiation
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  3. #3
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    Quote Originally Posted by skeeter View Post
    implicit differentiation
    how do you do that, i had a huge amount of trouble with that previously and got destroyed big time on that part of a test earlier in the year.
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    Quote Originally Posted by Da Freak View Post
    how do you do that, i had a huge amount of trouble with that previously and got destroyed big time on that part of a test earlier in the year.
    \frac{d}{dx} (x^2y^2+2y=x^3)

    x^2 \cdot 2y \cdot \frac{dy}{dx} + y^2 \cdot 2x + 2 \cdot \frac{dy}{dx} = 3x^2

    2x^2y \cdot \frac{dy}{dx} + 2 \cdot \frac{dy}{dx} = 3x^2 - 2xy^2

    \frac{dy}{dx}(2x^2y + 2) = 3x^2 - 2xy^2

    \frac{dy}{dx} = \frac{3x^2 - 2xy^2}{2x^2y + 2}
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    Quote Originally Posted by skeeter View Post
    \frac{d}{dx} (x^2y^2+2y=x^3)

    x^2 \cdot 2y \cdot \frac{dy}{dx} + y^2 \cdot 2x + 2 \cdot \frac{dy}{dx} = 3x^2

    2x^2y \cdot \frac{dy}{dx} + 2 \cdot \frac{dy}{dx} = 3x^2 - 2xy^2

    \frac{dy}{dx}(2x^2y + 2) = 3x^2 - 2xy^2


    \frac{dy}{dx} = \frac{3x^2 - 2xy^2}{2x^2y + 2}
    thanks a lot man, i really appreciate the help.
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