Implicit differentiation

**Da Freak** · December 16th 2009, 04:35 PM

could you tell me how to attack this one

**skeeter** · December 16th 2009, 04:43 PM

Originally Posted by Da Freak

thanks a lot man.

could you tell me how to attack this one too

implicit differentiation

**Da Freak** · December 16th 2009, 04:46 PM

Originally Posted by skeeter

implicit differentiation

how do you do that, i had a huge amount of trouble with that previously and got destroyed big time on that part of a test earlier in the year.

**skeeter** · December 16th 2009, 04:57 PM

Originally Posted by Da Freak

how do you do that, i had a huge amount of trouble with that previously and got destroyed big time on that part of a test earlier in the year.

$\frac{d}{dx} (x^2y^2+2y=x^3)$

$x^2 \cdot 2y \cdot \frac{dy}{dx} + y^2 \cdot 2x + 2 \cdot \frac{dy}{dx} = 3x^2$

$2x^2y \cdot \frac{dy}{dx} + 2 \cdot \frac{dy}{dx} = 3x^2 - 2xy^2$

$\frac{dy}{dx}(2x^2y + 2) = 3x^2 - 2xy^2$

$\frac{dy}{dx} = \frac{3x^2 - 2xy^2}{2x^2y + 2}$

**Da Freak** · December 16th 2009, 05:50 PM

Originally Posted by skeeter

$\frac{d}{dx} (x^2y^2+2y=x^3)$

$x^2 \cdot 2y \cdot \frac{dy}{dx} + y^2 \cdot 2x + 2 \cdot \frac{dy}{dx} = 3x^2$

$2x^2y \cdot \frac{dy}{dx} + 2 \cdot \frac{dy}{dx} = 3x^2 - 2xy^2$

$\frac{dy}{dx}(2x^2y + 2) = 3x^2 - 2xy^2$

$\frac{dy}{dx} = \frac{3x^2 - 2xy^2}{2x^2y + 2}$

thanks a lot man, i really appreciate the help.

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