Originally Posted by

**gocubs526** Hi guys! I'm doing my Calc homework right now and am having a little trouble with some problems. I did one but I'm not really sure if i did it right. Could you check for me?

∫Sin^5(2x)Cos(2x)

U= Sin(2x)

Du/Dx= Cos(2x)/2

Dx= du/2cos(2x)

(U)^5 Cos(2x) Du/Cos(2x)/2

So the Cos(2x) cancels and I’m left with

½ (U)^5

Now I have to do the anti derivative

**1/12(**U^6**)**

1/2Sin^6(2x) ?

I think you mean $\displaystyle \textcolor{red}{\frac{\sin^6(2x)}{12} + C}$

Is that right? If not, what did I do wrong?