Hi i need to differentiate the following function: f(x) = e^x . (x+2) . (x-1) I know the answer is f'(x) = e^x (x^2 + 3x -1) But have no idea how to get to this! Any help please?
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Plus then i need to make f'(x) = 0 and find that x = -3.30 and x = 0.30 :\
I think the function looks like this: If I'm correct, then the derivative is where . This is the chain rule. It's difficult to read what you typed. You should try to use the latex.
No sorry the question is f(x) = (e^x) . (x+2) . (x-1) and answer is f'(x) = (e^x) (x^2 + 3x -1)
If the equation is Then
Thanks for everyones help ive got it sorted now! Need help with this now! Whats the derivative of: Sin ( (x^2) + x )
Lets say and Now
so the answer is.. (2x + 1) . cos( (x^2) + x ) Is that right?
Okay so i swear the answer to this question is wrong! Bit of integration instead of differentiation! and the answer is Whereas I would have said it was Any help?
Originally Posted by xxJaRxx so the answer is.. (2x + 1) . cos( (x^2) + x ) Is that right? Good work!
Originally Posted by xxJaRxx Okay so i swear the answer to this question is wrong! Bit of integration instead of differentiation! and the answer is Whereas I would have said it was Any help? Read this Integration by parts - Wikipedia, the free encyclopedia For In your case make and now find and
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