Hi i need to differentiate the following function:
f(x) = e^x . (x+2) . (x-1)
I know the answer is
f'(x) = e^x (x^2 + 3x -1)
But have no idea how to get to this! Any help please?
I think the function looks like this:
$\displaystyle f(x)=e^{x(x+2)(x-1)}$
If I'm correct, then the derivative is $\displaystyle f'(x)=e^u\frac{du}{dx}$ where $\displaystyle u=x(x+2)(x-1)$. This is the chain rule.
It's difficult to read what you typed. You should try to use the latex.
Okay so i swear the answer to this question is wrong!
Bit of integration instead of differentiation!
$\displaystyle \int3xsin(7-x) dx$
and the answer is
$\displaystyle 3xcos(7-x) + 3sin(7-x) + c$
Whereas I would have said it was
$\displaystyle 3xsin(7-x) - 3cos(7-x) + c$
Any help?
Read this Integration by parts - Wikipedia, the free encyclopedia
For $\displaystyle \int uv' = uv - \int vu'$
In your case make $\displaystyle u=3x $ and $\displaystyle v' = \sin(7-x)$
now find $\displaystyle u'$ and $\displaystyle v$