$\displaystyle \int {\frac{{dx}}
{{x(1 + \sqrt[3]{x})}} = 3\ln \left| {\frac{{\sqrt[3]{x}}}
{{1 + \sqrt[3]{x}}}} \right|} + c
$
i thought of using a u sub with u= cuberootx and du= dx/3x^2/3
but i can't seem to make it work
$\displaystyle \int {\frac{{dx}}
{{x(1 + \sqrt[3]{x})}} = 3\ln \left| {\frac{{\sqrt[3]{x}}}
{{1 + \sqrt[3]{x}}}} \right|} + c
$
i thought of using a u sub with u= cuberootx and du= dx/3x^2/3
but i can't seem to make it work