Thread: Area between two curves with abs value.

Is this integral setup correctly
y= 1-2x^2 y=|x|

A=2 integral(1/2,0) [1-2x^2-x]

getting the limits by
1-2x^2 = x x>0
(2x-1)(x+1)
x = +- 1/2

Originally Posted by swatpup32

Is this integral setup correctly
y= 1-2x^2 y=|x|

A=2 integral(1/2,0) [1-2x^2-x]

getting the limits by
1-2x^2 = x x>0
(2x-1)(x+1)
x = +- 1/2

Yep - looks good to me.