Is this integral setup correctly y= 1-2x^2 y=|x| A=2 integral(1/2,0) [1-2x^2-x] getting the limits by 1-2x^2 = x x>0 (2x-1)(x+1) x = +- 1/2
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Originally Posted by swatpup32 Is this integral setup correctly y= 1-2x^2 y=|x| A=2 integral(1/2,0) [1-2x^2-x] getting the limits by 1-2x^2 = x x>0 (2x-1)(x+1) x = +- 1/2 Yep - looks good to me.
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