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Math Help - Int. by parts (x-1)e^2x-1

  1. #1
    Junior Member
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    Int. by parts (x-1)e^2x-1

    Hi i have this question, which im pretty sure is done using integration by parts:

    \int (x-1)e^{2x-1}

    and i get this answer:

    \frac{1}{4} e^{2x-1}(2x-3)

    But my book says it should contain (2x-1) instead

    Can anyone see where i may have slipped up. If it helps i can post the steps i took?

    Thank you
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  2. #2
    Senior Member
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    Your answer is correct (just verified on Maple). I can't see any simplification do be done.

    Clearly, the book is wrong since d/dx (2x-1) = 2.
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  3. #3
    Junior Member
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    Thank you very much! Didn't think the book would be wrong - it's almost always me.
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