# Thread: Int. by parts (x-1)e^2x-1

1. ## Int. by parts (x-1)e^2x-1

Hi i have this question, which im pretty sure is done using integration by parts:

$\int (x-1)e^{2x-1}$

$\frac{1}{4} e^{2x-1}(2x-3)$

But my book says it should contain $(2x-1)$ instead

Can anyone see where i may have slipped up. If it helps i can post the steps i took?

Thank you

2. Your answer is correct (just verified on Maple). I can't see any simplification do be done.

Clearly, the book is wrong since d/dx (2x-1) = 2.

3. Thank you very much! Didn't think the book would be wrong - it's almost always me.