Integrate the following using substitution:

2x / (x^4 + 3) dx

Here's how i started:

Let u = x^4 + 3

So du = 4x^3 dx

Now I have 2x / u dx

Do I multiply 2x by 2x^2 to get 4x^3 dx and substitute in with du?

If i do this I would have to mulitply the integral by 1/2x^2, but I'm not sure if I can do this...

Any advice..Thanks.