Find the lim as n-> infinity of 1 / (n^2 - n)
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See here & scroll down 1/(n^2 - n) - Wolfram|Alpha
Originally Posted by jzellt Find the lim as n-> infinity of 1 / (n^2 - n) Divide both numerator and denominator by $\displaystyle n^2$: $\displaystyle \frac{\frac{1}{n^2}}{1- \frac{1}{n}}$. Now the numerator goes to 0 while the denominator goes to 1.
Last edited by Jameson; Dec 15th 2009 at 01:05 PM.
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