Find the lim as n-> infinity of 1 / (n^2 - n)
Follow Math Help Forum on Facebook and Google+
See here & scroll down 1/(n^2 - n) - Wolfram|Alpha
Originally Posted by jzellt Find the lim as n-> infinity of 1 / (n^2 - n) Divide both numerator and denominator by : . Now the numerator goes to 0 while the denominator goes to 1.
Last edited by Jameson; Dec 15th 2009 at 01:05 PM.
View Tag Cloud