# limit Problem

• December 14th 2009, 10:36 PM
jzellt
limit Problem
Find the lim as n-> infinity of 1 / (n^2 - n)
• December 15th 2009, 01:30 AM
tom@ballooncalculus
See here & scroll down

1/(n^2 - n) - Wolfram|Alpha
• December 15th 2009, 03:08 AM
HallsofIvy
Quote:

Originally Posted by jzellt
Find the lim as n-> infinity of 1 / (n^2 - n)

Divide both numerator and denominator by $n^2$: $\frac{\frac{1}{n^2}}{1- \frac{1}{n}}$.

Now the numerator goes to 0 while the denominator goes to 1.