I have a quick question regarding implicit differentiation:
Heres the problem and its solution
What I dont understand is from the 1st step (First arrow) to the second, in particular why the x^2 turns into y^2 in 2xycos(y^2). The same goes on the right side. Why isnt it y'[2xycos(x^2)+sin(x^2)]=-sin(y^2)-2xycos(y^2)?
Also, on the right side there is a y' which seems to disappear?
Thanks in advance.