x^1/3 + x. I need to find the second derivative. I came up with -2/ 3x^2/3 for the first..
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Originally Posted by av8or91 x^1/3 + x. I need to find the second derivative. I came up with -2/ 3x^2/3 for the first.. For differentiation multiply by the exponent before taking one from said exponent $\displaystyle \frac{d}{dx}(\sqrt [3]{x} +x) = \frac{1}{3\sqrt [3]{x^2}}+1$
Originally Posted by av8or91 x^1/3 + x. I need to find the second derivative. I came up with -2/ 3x^2/3 for the first.. Just use the rule: If $\displaystyle y = ax^n$ then $\displaystyle \frac{dy}{dx} = anx^{n - 1}$. So $\displaystyle y = x^{\frac{1}{3}} + x$ $\displaystyle \frac{dy}{dx} = \frac{1}{3}x^{-\frac{2}{3}} + 1$ $\displaystyle \frac{d^2y}{dx^2} = -\frac{2}{9}x^{-\frac{5}{3}}$.
Thanks, basically trying to find concave up and concave down then the inflection points.
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