Lim (x-->0) [2-e^3x]^1/x = I.F 1^Inf.

Lim (x-->0) 1/x Ln(2-e^3x)= I.F. Inf. * 0

Lim(x-->0) x^-1 Ln (2-e^3x) = Ln (2-e^3x)/(1/x^-1)

I don't think I did that last step right. a little insight would be great. Thanks

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- December 14th 2009, 08:40 AMbgonzal8L'hopitals rule
Lim (x-->0) [2-e^3x]^1/x = I.F 1^Inf.

Lim (x-->0) 1/x Ln(2-e^3x)= I.F. Inf. * 0

Lim(x-->0) x^-1 Ln (2-e^3x) = Ln (2-e^3x)/(1/x^-1)

I don't think I did that last step right. a little insight would be great. Thanks - December 14th 2009, 08:46 AMbgonzal8
i think i got it .

Lim (Ln(2-e^3x)/x = (3e^3x)/2-e^3x = 3/1 = 3 ... is that right?

x-->0