Integrate the following equation

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December 14th 2009, 02:43 AM
zorro

Integrate the following equation

Question : Integrate $\int_{-1}^{1} |1- x| dx$
December 14th 2009, 02:47 AM
mr fantastic

Quote:

Originally Posted by zorro

Question : Integrate $\int_{-1}^{1} |1- x| dx$

Note that $|1 - x| = 1 - x$ when $x < 1$ and | $1 - x| = -(1 - x) = x - 1$ when $x \geq 1$ .
December 14th 2009, 03:51 AM
Krizalid

or note that the integrand is non-negative for $-1\le x\le1,$ so the absolute value is irrelevant there and you can simply evaluate $\int_{-1}^1(1-x)\,dx.$
December 14th 2009, 04:05 AM
Raoh

Quote:

Originally Posted by zorro

Question : Integrate $\int_{-1}^{1} |1- x| dx$

$\forall x\in [-1,1],1-x\geq 0$
December 14th 2009, 11:18 AM
zorro

Is this correct?

Quote:

Originally Posted by Raoh

$\forall x\in [-1,1],1-x\geq 0$

$\int_{-1}^{1} |1-x|dx \$ = $\int_{-1}^{1} (1-x)dx$ = ........ = $2$

Is this correct???
December 14th 2009, 11:28 AM
Raoh

Quote:

Originally Posted by zorro

$\int_{-1}^{1} |1-x|dx \$ = $\int_{-1}^{1} (1-x)dx$ = ........ = $2$

Is this correct???

i believe you're right(Nod)

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