1. ## What is this question asking?

The position of an object in free fall near the surface of the plane where the acceleration due to gravity has a constant magnitude of g(length-units)/sec^2 is given by the equation:
$s=- \frac{1}{2}gt^2+v_0t+s_0$, where s is the height above the earth, $v_0$ is the initial velocity and $s_0$ is the initial height. Give the initial value problem for this situation. Solve it to check its validity. Remember the positive direction is the upward direction.

I kno about the relationship between distance, speed, velocity, acceleration. But i am confused here as to what is being asked. Help please??

2. Originally Posted by Ife
The position of an object in free fall near the surface of the plane where the acceleration due to gravity has a constant magnitude of g(length-units)/sec^2 is given by the equation:
$s=- \frac{1}{2}gt^2+v_0t+s_0$, where s is the height above the earth, $v_0$ is the initial velocity and $s_0$ is the initial height. Give the initial value problem for this situation. Solve it to check its validity. Remember the positive direction is the upward direction.

I kno about the relationship between distance, speed, velocity, acceleration. But i am confused here as to what is being asked. Help please??
I'm not sure but I think the problem wants you to show that if you integrate the acceleration function you get the velocity function, if you integrate the velocity function you get the position function.