The position of a particle moving on the x axis is given by x(t)=t^2-5sin(0.8t). for what value of t is the particle furthest left?
I derived the function to get the velocity function and found that -1.77 is the correct answer.
A function has a derivative given by f '(x)= sqrt(x)/x^2+x+1. What is the x cooridnate of the inflection point of f?
e. no inflection point
I graphed it on my graphing calculator and got 0.434.
Can someone tell me if these answers are correct?