Originally Posted by

**Jon911** The position of a particle moving on the x axis is given by x(t)=t^2-5sin(0.8t). for what value of t is the particle furthest left?

a. -1.77

b. -1.287

c. 1.287

d. 1.177

e. 1.391

I derived the function to get the velocity function and found that -1.77 is the correct answer.

incorrect ... the particle is farthest to the left when x(t) is a minimum.

A function has a derivative given by f '(x)= sqrt(x)/x^2+x+1. What is the x cooridnate of the inflection point of f?

a. -0.768

b. 0

c. 0.434

d. 1

e. no inflection point

I graphed it on my graphing calculator and got 0.434.

correct