# Find area of region

• December 13th 2009, 09:47 AM
Morgan82
Find area of region
Between -pi/3 and pi/3

Between
y = 1/2 (sect)^2
and
y = 4 (sint)^2

I got 2 root 3

This is one of my first times doing these problems. Can someone tell me if I am right?
• December 13th 2009, 10:09 AM
Jester
Quote:

Originally Posted by Morgan82
Between -pi/3 and pi/3

Between
y = 1/2 (sect)^2
and
y = 4 (sint)^2

I got 2 root 3

This is one of my first times doing these problems. Can someone tell me if I am right?

This is what I got

$
\int_{-\pi/3}^{\pi/3} \frac{1}{2} \sec^2 t - 4 \sin^2 t\, dt = 2 \sqrt{3} - \frac{4 \pi}{3}.
$